# Line slope calculator 2x+3y=9

**Straight line given by points A[0; 3] and B[3; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.6667x+3

**Canonical form of the line equation:**2x+3y-9 = 0

**Parametric form of the line equation:**

x = 3t

y = -2t+3 ; t ∈ R

**Slope:**m = -0.6667

**Slope angle of line: φ =**-33°41'24″ = -0.588 rad

**X intercept:**x

_{0}= 4.5

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 2.4962

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; -2)

**Normal vector: n =**(2; 3)

**Midpoint of the segment AB: M =**[1.5; 2]

**Perpendicular Bisector equation:**3x-2y-0.5 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (3; 1) ; |OB| = 3.1623**

**Scalar product OA .OB = 3**

**Angle ∠ AOB = 71°33'54″ = 1.249 rad**